Q126 / 170 · Manipal (MET) 2020 · Physics

The displacement-time graph of a particle moving along a straight line is shown in the figure. Figure
The acceleration-time graph of this particle is

  • A
    Figure
  • Correct answer
    B
    Figure
  • C
    Figure
  • D
    Figure

Solution

Given, $x=9 t^2$ $\therefore \quad v=\frac{d x}{d t}=\frac{d}{d t}\left(9 t^2\right)=\frac{9 d}{d t}\left(t^2\right)=18 t$ also, $\quad a=\frac{d^2 x}{d t^2}=\frac{d v}{d t}=\frac{d}{d t}(18 t)=18$

Hence, the correct answer is option: 'B'.

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