Q186 / 225 · JEE Main 2003 · Physics
The displacement $y$ of a wave travelling in the $x$-direction is given by $y=10^{-4} \sin \left(600 t-2 x+\frac{\pi}{3}\right)$ metres where $\mathrm{x}$ is expressed in metres and $\mathrm{t}$ in seconds. The speed of the wave-motion, in $\mathrm{ms}^{-1}$, is
- A$300$
- Correct answerB$600$
- C$1200$
- D$200$
Solution
$y=10^{-4} \sin \left(600 t-2 x+\frac{\pi}{3}\right)$. Comparing it with standard equation
$y=A \sin (v t-k x) ; \quad v=600 m / s$
Hence, the correct answer is option: 'B'.