The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B_1 . When the dipole moment is…

Question

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B_1 . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B_2 . The ratio B_1/B_2 is:

MARKS Content Team · Accepted Answer

Correct answer: (D) √2. m=magnetic dipole moment=IA. For Loop_1, m=Iπr^2, B_1=(μ_0i)/2r For Loop_2. If current is constant m is doubled. r^1 =√2 r . B_2 =(μ_0 i)/(2√2 r) .B_1/B_2=√2

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is:

Solution

Relevant Questions

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is B1 . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is B2 . The ratio B1B2 is:

Solution

Relevant Questions

The dipole moment of a circular loop carrying a current I, is m and the magnetic field at the centre of the loop is $B_{1}$ . When the dipole moment is doubled by keeping the current constant, the magnetic field at the centre of the loop is $B_{2}$ . The ratio $\frac{B_{1}}{B_{2}}$ is: