Q3 / 92 · NTA Abhyas (JEE Main) 2020 · Physics · Units and Dimensions

The dimensional formula for entropy is

A
[ $M L T^{- 2} K^{- 1}$ ]
B
[ $M L^{2} T^{- 2}$ ]
Correct answer
C
[ $M L^{2} T^{- 2} K^{- 1}$ ]
D
[ $M L^{- 2} T^{- 2} K^{- 1}$ ]

Solution

E n t r o p y = \frac{h e a t}{t e m p e r a t u r e}

(Δ Q = T Δ S)

[Entropy]=

\frac{Q}{T} = \frac{[M L^{2} T^{- 2}]}{[K]} = [M L^{2} T^{- 2} K^{- 1}]

Hence, the correct answer is option: 'C'.

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