Q122 / 160 · TS EAMCET 2020 (11 Sep Shift 2) · Physics

The dimension of angular momentum in mass $(M)$, length $(L)$ and time $(T)$ is

  • A
    $\left[\mathrm{MLT}^{-1}\right]$
  • B
    $\left[\mathrm{ML}^{-1} \mathrm{~T}^{-1}\right]$
  • Correct answer
    C
    $\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$
  • D
    $\left[\mathrm{ML}^{-1} \mathrm{~T}^{-2}\right]$

Solution

Angular momentum for a point mass about an axis with velocity component of $v$ perpendicular to the radial direction is given by Angular momentum, $L=m v r$ Dimension formula of angular momentum $=[\mathrm{M}]\left[\mathrm{LT}^{-1}\right][\mathrm{L}]=\left[\mathrm{ML}^2 \mathrm{~T}^{-1}\right]$

Hence, the correct answer is option: 'C'.

Relevant Questions