Q118 / 160 · AP EAMCET 2024 (21 May Shift 2) · Mathematics
The differential equation formed by eliminating arbitrary constants $\mathrm{A}, \mathrm{B}$ from the equation $y=A \cos 3 x+\mathrm{B} \sin 3 x$ is
- A$\frac{d^2 y}{d x^2}+y=0$
- Correct answerB$\frac{d^2 y}{d x^2}+9 y=0$
- C$\frac{d^2 y}{d x^2}-9 y=0$
- D$\frac{d^2 y}{d x^2}-y=0$
Solution
$\begin{aligned} & y=A \cos 3 x+B \sin 3 x \Rightarrow \frac{d y}{d x}=-3 A \sin 3 x+3 B \cos 3 x \\ & \frac{d^2 y}{d x^2}=-9 A \cos 3 x-9 B \sin 3 x=-9 y \\ & \Rightarrow \frac{d^2 y}{d x^2}+9 y=0 \text {. }\end{aligned}$
Hence, the correct answer is option: 'B'.