Q22 / 69 · JEE Advanced 2011 (Paper 1) · Chemistry
The difference in the oxidation numbers of the two types of sulphur atoms in $\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6$ is
Correct answer: 5
Solution
$$
\mathrm{Na}_2 \mathrm{~S}_4 \mathrm{O}_6 \text { is a salt of } \mathrm{H}_2 \mathrm{~S}_4 \mathrm{O}_6 \text { which has the following structure }
$$
$$ \Rightarrow \text { Difference in oxidation number of two types of sulphur }=5 $$
$$ \Rightarrow \text { Difference in oxidation number of two types of sulphur }=5 $$
Hence, the correct answer is 5.