Q40 / 150 · JEE Main 2006 · Chemistry

The decreasing values of bond angles from $\mathrm{NH}_3\left(106^{\circ}\right)$ to $\mathrm{SbH}_3\left(101^{\circ}\right)$ down group-15 of the periodic table is due to

  • A
    increasing bp-bp repulsion
  • B
    increasing p-orbital character in $\mathrm{sp}^3$
  • C
    decreasing Ip-bp repulsion
  • Correct answer
    D
    decreasing electronegativity

Hence, the correct answer is option: 'D'.

Relevant Questions