Q51 / 75 · JEE Main 2020 (09 Jan Shift 2) · Physics

The current $i$ in the network is

A
$0.2 A$
B
$0.6 A$
Correct answer
C
$0.3 A$
D
$0 A$

Solution

Both the diodes are in reverse biased.

I = \frac{9}{30} = \frac{3}{10} A = 0.3 A

Hence, the correct answer is option: 'C'.

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