Q139 / 150 · MHT CET 2019 (Shift 2) · Physics

The critical angle for light going from medium ‘x’ to medium ‘y’ is 'θ' . The speed of light in medium ‘x’ is 'vx' . The speed of light in medium ‘y’ is

  • A
    vxtanθ
  • B
    vxsinθ
  • C
    vxtanθ
  • Correct answer
    D
    vxsinθ

Solution

The critical angle is that angle on incidence in the denser medium for which the angle of refraction in rarer medium is 90o,i.e.
sinθsin90o=μyμx
⇒sinθ=μyμx …. (i)
Where, μ= refractive index of medium.
Also,μ=speedoflightinvacuumspeedoflightinmedium=cv … (ii)
Form Eqs. (i) and (ii), we get
sinθcvy×vxc=vxvy⇒vy=vxsinθ

Hence, the correct answer is option: 'D'.

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