Q90 / 270 · NDA 2020 · General Ability

The cost of energy to operate an industrial refrigerator that consumes 5 kW power working 10 hours per day for 30 days will be (Given that the charge per kW.h of energy =₹ 4)

  • A
    ₹ 600
  • Correct answer
    B
    ₹ 6,000
  • C
    ₹ 1,200
  • D
    ₹ 1,500

Solution

The total energy consumption in a month is given by, $5 \times 10 \times 30=1500 \mathrm{Kwh}$. As the charge per kWh of energy is $₹ 4$, hence for 1500 Kwh it will be $1500 \times 4=$ ₹ 6000.

Hence, the correct answer is option: 'B'.

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