The correct truth table for the given input data of the following logic gate is :
Inputs

• A

  \(\begin{array}{|c|c|c|c|c|} \hline A & B & C & D & Y \\ \hline 1 & 1 & 0 & 1 & 0 \\ \hline 0 & 0 & 1 & 1 & 0 \\ \hline 1 & 0 & 1 & 0 & 1 \\ \hline 1 & 1 & 1 & 1 & 1 \\ \hline \end{array}\)
• B

  \(\begin{array}{|c|c|c|c|c|} \hline A & B & C & D & Y \\ \hline 1 & 1 & 0 & 1 & 0 \\ \hline 0 & 0 & 1 & 1 & 1 \\ \hline 1 & 0 & 1 & 0 & 1 \\ \hline 1 & 1 & 1 & 1 & 1 \\ \hline \end{array}\)
• Correct answer
  C

  \(\begin{array}{|c|c|c|c|c|} \hline A & B & C & D & Y \\ \hline 1 & 1 & 0 & 1 & 1 \\ \hline 0 & 0 & 1 & 1 & 0 \\ \hline 1 & 0 & 1 & 0 & 0 \\ \hline 1 & 1 & 1 & 1 & 1 \\ \hline \end{array}\)
• D

  \(\begin{array}{|c|c|c|c|c|} \hline A & B & C & D & Y \\ \hline 1 & 1 & 0 & 1 & 1 \\ \hline 0 & 0 & 1 & 1 & 0 \\ \hline 1 & 0 & 1 & 0 & 1 \\ \hline 1 & 1 & 1 & 1 & 0 \\ \hline \end{array}\)

Hence, the correct answer is option: 'C'.