Q8 / 120 · VITEEE 2016 · Chemistry

The correct set of quantum numbers for $\mathrm{Rb}$ (atomic no. 37 ) is

  • Correct answer
    A
    $5,0,0,-\frac{1}{2}$
  • B
    $5,1,0, \frac{1}{2}$
  • C
    $6,0,1, \frac{1}{2}$
  • D
    $5,1,1, \frac{1}{2}$

Solution

The electronic configuration for Rb (37) is $\begin{array}{l} \operatorname{Rb}(37) \\ =1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{1} \\ \text { For } 5 s^{1}, n=5, \ell=0, m=0, s=\frac{1}{2} \end{array}$

Hence, the correct answer is option: 'A'.

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