Q8 / 120 · VITEEE 2016 · Chemistry
The correct set of quantum numbers for $\mathrm{Rb}$ (atomic no. 37 ) is
- Correct answerA$5,0,0,-\frac{1}{2}$
- B$5,1,0, \frac{1}{2}$
- C$6,0,1, \frac{1}{2}$
- D$5,1,1, \frac{1}{2}$
Solution
The electronic configuration for Rb (37) is
$\begin{array}{l}
\operatorname{Rb}(37) \\
=1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 4 s^{2} 3 d^{10} 4 p^{6} 5 s^{1} \\
\text { For } 5 s^{1}, n=5, \ell=0, m=0, s=\frac{1}{2}
\end{array}$
Hence, the correct answer is option: 'A'.