Q5 / 160 · TS EAMCET 2022 (19 Jul Shift 2) · Chemistry

The correct order of the bond angles of the compounds $\mathrm{SiCl}_4, \mathrm{BF}_3, \mathrm{BeCl}_2$ and $\mathrm{SF}_6$ is

  • A
    $\mathrm{BF}_3>\mathrm{BeCl}_2>\mathrm{SF}_6>\mathrm{SiCl}_4$
  • B
    $\mathrm{BeCl}_2>\mathrm{SF}_6>\mathrm{SiCl}_4>\mathrm{BF}_3$
  • C
    $\mathrm{BeCl}_2>\mathrm{SiCl}_4>\mathrm{BF}_3>\mathrm{SF}_6$
  • Correct answer
    D
    $\mathrm{BeCl}_2>\mathrm{BF}_3>\mathrm{SiCl}_4>\mathrm{SF}_6$

Solution

$\mathrm{BeCl}_2$ has linear structure. So, the bond angle is $180^{\circ}$. $\mathrm{BF}_3$ has trigonal planar structure. So, the bond angle is $120^{\circ}$. $\mathrm{SiCl}_4$ has tetrahedral structure. So, the bond angle is $109.5^{\circ}$. $\mathrm{SF}_6$ has octahedral structure. So, the bond angle is $90^{\circ}$. Therefore, the correct order is $\mathrm{BeCl}_2>\mathrm{BF}_3>\mathrm{SiCl}_4>\mathrm{SF}_6$.

Hence, the correct answer is option: 'D'.

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