Q59 / 180 · AIIMS 2002 · Chemistry

The correct order of solubility in water for $\mathrm{He}$, $\mathrm{Ne}, \mathrm{Ar}, \mathrm{Kr}$, Xe is

  • A
    $\mathrm{He}>\mathrm{Ne}>\mathrm{Ar}>\mathrm{Kr}>\mathrm{Xe}$
  • Correct answer
    B
    $\mathrm{Xe}>\mathrm{Kr}>\mathrm{Ar}>\mathrm{Ne}>\mathrm{He}$
  • C
    $\mathrm{Ne}>\mathrm{Ar}>\mathrm{Kr}>\mathrm{He}>\mathrm{Xe}$
  • D
    $\mathrm{Ar}>\mathrm{Ne}>\mathrm{He}>\mathrm{Kr}>\mathrm{Xe}$.

Solution

As the size of the noble gas atoms increases down the group, the polarisation of the electron cloud becomes easier. So heavier noble gas atoms are easily polarised in polar water.

Hence, the correct answer is option: 'B'.

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