Q37 / 180 · AIIMS 2008 · Chemistry

The correct order of dipole moment is

  • Correct answer
    A
    \(\mathrm{CH}_4 < \mathrm{NF}_3 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O}\)
  • B
    \(\mathrm{NF}_3 < \mathrm{CH}_4 < \mathrm{NH}_3 < \mathrm{H}_2 \mathrm{O}\)
  • C
    \(\mathrm{NH}_3 < \mathrm{NF}_3 < \mathrm{CH}_4 < \mathrm{H}_2 \mathrm{O}\)
  • D
    \(\mathrm{H}_2 \mathrm{O} < \mathrm{NH}_3 < \mathrm{NF}_3 < \mathrm{CH}_4\).

Solution

In $\mathrm{H}_2 \mathrm{O}$, electronegativity difference is highest. So, dipole moment is highest in this. $\mathrm{CH}_4$ is a symmetrical tetrahedral structure and its dipole moment is zero.

Hence, the correct answer is option: 'A'.

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