Q25 / 155 · WBJEE 2024 · Chemistry

The correct order of boiling point of the given aqueous solution is

  • A
    \(1 \mathrm{~N} \mathrm{KNO}_3>1 \mathrm{~N} \mathrm{NaCl} >1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
  • Correct answer
    B
    \(1 \mathrm{~N} \mathrm{KNO}_3=1 \mathrm{~N} \mathrm{NaCl} >1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)
  • C
    Same for all
  • D
    \(1 \mathrm{~N} \mathrm{KNO}_3=1 \mathrm{~N} \mathrm{NaCl} =1 \mathrm{~N} \mathrm{CH}_3 \mathrm{COOH} >1 \mathrm{~N} \text { sucrose }\)

Solution

Hint : Elevation in boiling point $\propto$ No. of solute particles $\mathrm{KNO}_3$ (strong electrolyte); $\mathrm{KNO}_{3(\text { (aq) }} \rightarrow \mathrm{K}_{(\mathrm{aq})}^{+}+\mathrm{NO}_{3 \text { (aq) }}^{-}$ NaCl (Strong electrolyte); $\mathrm{NaCl}_{(\mathrm{aq})} \rightarrow \mathrm{Na}_{\text {(aq) }}^{+}+\mathrm{Cl}_{\text {(aq) }}$ $\mathrm{CH}_3 \mathrm{COOH}$ (Weak electrolyte); $\mathrm{CH}_3 \mathrm{COOH}_{(\mathrm{aq})} \rightleftharpoons \mathrm{CH}_3 \mathrm{COO}_{(\text {aq) }}+\mathrm{H}_{\text {(aq) }}^{+}$ Sucrose (Non-electrolyte)

Hence, the correct answer is option: 'B'.

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