Q4 / 160 · AP EAMCET 2023 (18 May Shift 1) · Chemistry

The correct order of atomic radii of $\mathrm{B}, \mathrm{Be}, \mathrm{N}$ and $\mathrm{C}$ is

  • A
    $\mathrm{Be} < \mathrm{B} < \mathrm{C} < \mathrm{N}$
  • B
    $\mathrm{N} < \mathrm{B} < \mathrm{C} < \mathrm{Be}$
  • Correct answer
    C
    $\mathrm{N} < \mathrm{C} < \mathrm{B} < \mathrm{Be}$
  • D
    $\mathrm{Be} < \mathrm{C} < \mathrm{B} < \mathrm{N}$

Solution

Atomic radii generally decreases in a period from left to right due to an increase in the effective nuclear charge. Thus, ${ }_7 \mathrm{~N} < { }_6 \mathrm{C} < { }_5 \mathrm{~B} < { }_4 \mathrm{Be}$

Hence, the correct answer is option: 'C'.

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