The correct hybridization of $\mathrm{F}\mathrm{e}$ in complex ${\text{K}}_{\text{3}}{\text{[Fe(CN)}}_{\text{6}}\text{]}$ is

• A

  $\mathrm{d}\mathrm{s}{\mathrm{p}}^3$
• B

  $\mathrm{s}{\mathrm{p}}^3$
• C

  $\mathrm{s}{\mathrm{p}}^3{\mathrm{d}}^2$
• Correct answer
  D

  ${\mathrm{d}}^2\mathrm{s}{\mathrm{p}}^3$

Solution

${\mathrm{K}}_3\left[\mathrm{F}\mathrm{e}\right(\mathrm{C}\mathrm{N}{)}_6]$

Electronic configuration of $\mathrm{F}\mathrm{e}=\left[\mathrm{A}\mathrm{r}\right]4{\mathrm{s}}^{2}3{\mathrm{d}}^6$

Electronic configuration of $\mathrm{F}{\mathrm{e}}^{+3}=\left[\mathrm{A}\mathrm{r}\right]3{\mathrm{d}}^5$

Number of ligand (coordination numbr) $=6$

Nature of ligand is strong field.



Hybridization of $\mathrm{F}\mathrm{e}$ is ${\mathrm{d}}^2\mathrm{s}{\mathrm{p}}^3$ .

Hence, the correct answer is option: 'D'.