Q5 / 160 · AP EAMCET 2024 (18 May Shift 1) · Chemistry

The correct formula used to determine the formal charge $\left(\mathrm{Q}_{\mathrm{f}}\right)$ on an atom in the given Lewis structure of a molecule or ion is ( $\mathrm{V}=$ number of valence electrons in free atom, $\mathrm{U}=$ number of unshared electrons on the atom, $\mathrm{B}=$ number of bonds around the atom)

  • A
    $\mathrm{Q}_{\mathrm{f}}=\mathrm{V}-\left(\frac{\mathrm{U}}{\mathrm{B}}\right)$
  • B
    $\mathrm{Q}_{\mathrm{f}}=\mathrm{V}+(\mathrm{U}-\mathrm{B})$
  • Correct answer
    C
    $\mathrm{Q}_{\mathrm{f}}=\mathrm{V}-(\mathrm{U}+\mathrm{B})$
  • D
    $\mathrm{Q}_{\mathrm{f}}=\mathrm{V}-\left(\frac{\mathrm{B}}{\mathrm{U}}\right)$

Solution

Formal charge $\left(Q_f\right)$ on an atom $=[$ Total number of valence electron in the free atom (v)] -[total number of non bonding/unshared electron] -[number of bond around the atom] $\begin{aligned} & \therefore Q_f=V-(U)-(B) \\ & Q_f=V-(U+B)\end{aligned}$

Hence, the correct answer is option: 'C'.

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