Q3 / 160 · AP EAMCET 2022 (08 Jul Shift 2) · Chemistry
The correct electronic configuration of the element $\mathrm{Au}$ is
- A$[\mathrm{Xe}] 4 f^{14} 5 d^{10} 6 s^2$
- B$[\mathrm{Xe}] 4 f^{14} 5 d^9 6 s^2$
- Correct answerC$[\mathrm{Xe}] 4 f^{14} 5 d^{10} 6 s^1$
- D$[X e] 4 f^{14} 5 d^9 6 s^1$
Solution
The electronic configuration of the element $\mathrm{Au}$ is [Xe] $4 f^{14} 5 d^{10} 6 s^1$
Hence, the correct answer is option: 'C'.