Q124 / 180 · KCET 2018 · Physics
The correct Biot- Savart law in vector form is
- A\(\overline{\delta B}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{dl}(\overrightarrow{\mathrm{l}} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{3}}\)
- Correct answerB\(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{d} l} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{3}}\)
- C\(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{r}} \times \overrightarrow{\mathrm{d} l})}{\mathrm{r}^{3}}\)
- D\(\overline{\delta \mathrm{B}}=\frac{\mu_{0}}{4 \pi} \frac{\mathrm{I}(\overrightarrow{\mathrm{d} l} \times \overrightarrow{\mathrm{r}})}{\mathrm{r}^{2}}\)
Solution
Biot - Savart law describes magnetic field created by a current carrying conductor. Biot - Savart law in vector form is
\( d \vec{B}=\frac{\mu_{0}}{4 I I} \frac{I(d \vec{l} \times \vec{r})}{r^{3}} \)
\( d \vec{B}=\frac{\mu_{0}}{4 I I} \frac{I(d \vec{l} \times \vec{r})}{r^{3}} \)
Hence, the correct answer is option: 'B'.