Q36 / 72 · NTA Abhyas (JEE Main) 2020 · Physics · Motion In Two Dimensions

The coordinates of a moving particle at any time t are given by x = α t⁡ 3 and y⁡ = β t⁡ 3. The speed of the particle at time t is given by

  • A
    3 t⁡ α 2 + β 2
  • B
    t⁡ 2 α 2 + β 2
  • C
    α 2 + β 2
  • Correct answer
    D
    3 t⁡ 2 α 2 + β 2

Solution

∵ x = α t⁡ 3

∴d⁡xd⁡t⁡=3αt⁡2⇒vx=3αt⁡2 

Again y⁡ = β t⁡ 3

∴d⁡y⁡d⁡t⁡⇒vy⁡=3βt⁡2

Since, v2=vx2+vy2

v2=(3αt⁡2)2+(3βt⁡2)2=(3t⁡2)2(α2+β2)

Or v=3t⁡2α2+β2

Hence, the correct answer is option: 'D'.

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