Q48 / 160 · TS EAMCET 2014 · Mathematics

The condition for the lines $l x+m y+n=0$ and $l_1 x+m_1 y+n_1=0$ to be conjugate with respect to the circle $x^2+y^2=r^2$, is

  • Correct answer
    A
    $r^2\left(I_1+m m_1\right)=n n_1$
  • B
    $r^2\left(I_1-m m_1\right)=n n_1$
  • C
    $r^2\left(I_1+m m_1\right)+n n_1=0$
  • D
    $r^2\left(I m_1+I_1 m\right)=n n_1$

Solution

Condition for conjugate line is $$ r^2\left(I_1+m m_1\right)=n n_1 $$ Figure

Hence, the correct answer is option: 'A'.

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