Q48 / 160 · TS EAMCET 2014 · Mathematics
The condition for the lines $l x+m y+n=0$ and $l_1 x+m_1 y+n_1=0$ to be conjugate with respect to the circle $x^2+y^2=r^2$, is
- Correct answerA$r^2\left(I_1+m m_1\right)=n n_1$
- B$r^2\left(I_1-m m_1\right)=n n_1$
- C$r^2\left(I_1+m m_1\right)+n n_1=0$
- D$r^2\left(I m_1+I_1 m\right)=n n_1$
Solution
Condition for conjugate line is
$$
r^2\left(I_1+m m_1\right)=n n_1
$$


Hence, the correct answer is option: 'A'.