Q37 / 120 · VITEEE 2009 · Chemistry
The concentration of an organic compound in chloroform is $6.15 \mathrm{~g}$ per $100 \mathrm{~mL}$ of solution. A portion of this solution in a $5 \mathrm{~cm}$ polarimeter tube causes an observed rotation of $-1.2^{\circ}$. What is the specific rotation of the compound?
- A$+12^{\circ}$
- B$-3.9^{\circ}$
- Correct answerC$-39^{\circ}$
- D$+61.5^{\circ}$
Solution
$[\alpha]=\frac{[\alpha]_{\text {observed }}}{l \times C}=\frac{-1.2}{5 \times \frac{6.15}{1000}}=-39^{\circ}$
Hence, the correct answer is option: 'C'.