Q14 / 160 · AP EAMCET 2023 (18 May Shift 2) · Chemistry

The compounds having coordinated water are $\begin{array}{ccc}\mathrm{CrCl}_3 6 \mathrm{H}_2 \mathrm{O} & \mathrm{BaBl}_2 \cdot 2 \mathrm{H}_2 \mathrm{O} & \mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O} \\ \text { I } & \text { II } & \text { III }\end{array}$

  • A
    II, III only
  • Correct answer
    B
    I, III only
  • C
    I, II only
  • D
    I, II, III

Solution

$$ \begin{aligned} & \text {} \mathrm{CrCl}_3, 6 \mathrm{H}_2 \mathrm{O}=\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{Cl}_3,\left[\mathrm{Cr}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{Cl}\right] \\ & \mathrm{Cl}_2, \ldots \\ & \mathrm{BaCl}_2 \cdot 2 \mathrm{H}_2 \mathrm{O}=\mathrm{Ba}^{2+} 2 \mathrm{Cl}-2 \mathrm{H}_2 \mathrm{O} \\ & \mathrm{CuSO}_4 \cdot 5 \mathrm{H}_2 \mathrm{O}=\left[\mathrm{Cu}\left(\mathrm{H}_2 \mathrm{O}\right)_4\right] \mathrm{SO}_4 \ldots . \mathrm{H}_2 \mathrm{O} \end{aligned} $$ Thus, I and III have coordinated water.

Hence, the correct answer is option: 'B'.

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