Q11 / 150 · MHT CET 2009 · Chemistry

The compound from which formic acid cannot be prepared is

  • A
    methyl alcohol
  • B
    carbon monoxide $+\mathrm{NaOH}$
  • C
    glycerol
  • Correct answer
    D
    methyl magnesium bromide

Solution

Formic acid (HCOOH) cannot be prepared from methyl magnesium bromide $\left(\mathrm{CH}_{3} \mathrm{MgBr}\right)$ while from all other reagents, it is obtained as (a) $\quad \mathrm{CH}_{3} \mathrm{OH} \quad \stackrel{[\mathrm{O}]}{\longrightarrow} \mathrm{HCHO} \stackrel{[\mathrm{O}]}{\longrightarrow} \mathrm{HCOOH}$ methyl alcohol (b) $\mathrm{CO}+\mathrm{NaOH} \longrightarrow \mathrm{HCOONa} \frac{\mathrm{NaHSO}_{4}}{\Delta}$ $\mathrm{HCOOH}+\mathrm{Na}_{2} \mathrm{SO}_{4}$ (c) Glycerol + Oxalic acid $\frac{383 \mathrm{~K}}{\mathrm{H}_{2} \mathrm{O}}$ HCOOH $+$ glycerol

Hence, the correct answer is option: 'D'.

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