Q84 / 270 · NDA 2017 (Phase 2) · General Ability

The compound $\mathrm{C}_6 \mathrm{H}_{12} \mathrm{O}_4$ contains

  • A
    22 atoms per mole
  • B
    twice the mass precent of H as compared to the mass percent of $C$
  • Correct answer
    C
    six times the mass percent of C as compared to the mass percent of H
  • D
    thrice the mass percent of H as compared to the mass percent of $O$

Solution

There are $6.022 \times 1023$ entities in 1 mole. Atomic mass of Carbon $=12$ Atomic mass of Hydrogen $=1 \mid$ Atomic mass of Oxygen $=16$ Molecular mass $=(6 \times 12)+(12 \times$ 1) $+(4 \times 16)=72+12+64=148 \backslash$ Mass percentage of carbon $=72 / 148=49 \%$ Mass percentage of hydrogen $=12 / 148=8 \%$ Mass percentage of oxygen $=64 / 148=43 \%$

Hence, the correct answer is option: 'C'.

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