The complex, $\left[\mathrm{Pt}(\mathrm{Py})\left(\mathrm{NH}_3\right) \mathrm{BrCl}\right]$ will have how many geometrical isomers?

• A

  4
• B

  0
• C

  2
• Correct answer
  D

  3

Solution

The complex is square planar and is of the type $[M(a b c d)]$. It has three geometrical isomers.

Hence, the correct answer is option: 'D'.