Q36 / 180 · KCET 2022 · Chemistry
The complex hexamineplatinum(IV)chloride will give number of ions on ionisation.
- A4
- B3
- C2
- Correct answerD5
Solution
The formula of hexamineplatinum (IV) chloride is $\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_4$.
$$
\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_6\right] \mathrm{Cl}_4 \longrightarrow\left[\mathrm{Pt}\left(\mathrm{NH}_3\right)_6\right]^{4+}+4 \mathrm{Cl}^{-}
$$
Thus, five ions are produced.
Hence, the correct answer is option: 'D'.