Q24 / 91 · KVPY 2018 (SB/SX) · Chemistry

The complex having the highest spin only magnetic moment is

  • A
    FeCN63-
  • B
    FeH2O62+
  • Correct answer
    C
    MnF64-
  • D
    NiCl42-

Solution

The spin only magnetic moment for a complex can be calculated using formula

μ=nn+2

(a) FeCN63-

The oxidation number Fe in FeCN63- is +3 .The electronic configuration of Fe3+ is -Ar3d54s0

Figure

As CN- is a strong ligand pairing will occur.

FeCN63-

Figure

∴n=1⇒μ=11+2=3

(b) FeH2O62+

The oxidation number of Fe in

FeH2O62+ is +2 .The electronic configuration of Fe2+ is -Ar3d64s0

As H2O is weak ligand, so pairing will not occur.

FeH2O62-

Figure
n=4

μ=44+2=24

(c) MnF64-

The oxidation number of Mn is +2. It's
configuration is -Ar3d54s0

As F- is a weak field ligand, so pairing will not occur.

MnF64-

Figure
n=5

μ=55+2=35

(d) NiCl42-

In NiCl42-, the oxidation number of Ni will be +2. It's configuration is -Ar3d84s0

As Cl- is a weak field ligand, so pairing will not occur.

NiCl42-

Figure

n=2

μ=22+2=8

Thus, MnF64- will have the highest spin only magnetic moment.

Hence, the correct answer is option: 'C'.

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