Q9 / 90 · JEE Main 2021 (17 Mar Shift 2) · Chemistry

The common positive oxidation states for an element with atomic number $24,$ are:

Correct answer
A
$+ 2$ to $+ 6$
B
$+ 1$ and $+ 3$ to $+ 6$
C
$+ 1$ and $+ 3$
D
$+ 1$ to $+ 6$

Solution

$Cr (Z = 24)$

$[Ar] 4 s^{1} 3 d^{5} Cr$ shows common oxidation states starting from $+ 2$ to $+ 6$ .

Hence, the correct answer is option: 'A'.

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