Q66 / 180 · AIIMS 2017 · Chemistry

The colourless species is

  • A
    $\mathrm{VCl}_3$
  • B
    $\mathrm{VOSO}_4$
  • Correct answer
    C
    $\mathrm{Na}_3 \mathrm{VO}_4$
  • D
    $\left[\mathrm{V}\left(\mathrm{H}_2 \mathrm{O}\right)_6\right] \mathrm{SO}_4 \cdot \mathrm{H}_2 \mathrm{O}$

Solution

In $\mathrm{Na}_3 \mathrm{VO}_4$, vanadium is present in +5 oxidation state. $\mathrm{V}^{5+}: 3 d^0 4 s^0$, does not have unpaired electron. Hence, $\mathrm{Na}_3 \mathrm{VO}_4$, is colourless species.

Hence, the correct answer is option: 'C'.

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