Q10 / 268 · NTA Abhyas (NEET) 2020 · Physics · Thermodynamics

The coefficient of performance of a refrigerator working between $10 ° C$ and $20 ° C$ is

Correct answer
A
$28.3$
B
$29.3$
C
$2$
D
$0.5$

Solution

T_{1} = 273 + 20 = 293 K, T_{2} = 273 + 10 = 283 K

Coefficient of performance

= \frac{T_{2}}{T_{1} - T_{2}} = \frac{283}{293 - 283} = \frac{283}{10} = 28.3

Hence, the correct answer is option: 'A'.

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