Q100 / 160 · AP EAMCET 2003 · Mathematics
The coefficient of $x^5$ in the expansion of $\left(1+x^2\right)^5(1+x)^4$, is :
- Correct answerA60
- B50
- C40
- D56
Solution
We have,
$\left(1+x^2\right)^5(1+x)^4$
$=\left[1+{ }^5 C_1 x^2+{ }^5 C_2 x^4+\ldots+\left(x^2\right)^5\right]$
$\left[1+{ }^4 C_1 x+{ }^4 c_2 x^2+{ }^4 C_3 x^3+x^4\right]$
Coefficient of $x^5={ }^5 C_1 \cdot{ }^4 C_3+{ }^5 C_2 \cdot{ }^4 C_1$
$=5 \cdot 4+10 \cdot 4=20+40=60$
Hence, the correct answer is option: 'A'.