Q116 / 200 · Manipal (MET) 2011 · Mathematics
The circumcentre of a triangle formed by the lines $x y+2 x+2 y+4=0$ and $x+y+2=0$, is
- A$(0,-1)$
- B$(-1,0)$
- C$(1,1)$
- Correct answerD$(-1,-1)$
Solution
Given lines are
$x y+2 x+2 y+4=0$...(i)
and $\quad x+y+2=0$...(ii)

From Eqs. (i) and (ii), we get $x y=0$ $\Rightarrow \quad x=y=0$ $\therefore$ Vertices of triangle are $(-2,0),(0,0),(0,-2)$ In a right angled triangle circumcentre is the mid-point of hypotenuse. $\therefore$ Point $(-1,-1)$ is the required coordinate of the circumcentre.

From Eqs. (i) and (ii), we get $x y=0$ $\Rightarrow \quad x=y=0$ $\therefore$ Vertices of triangle are $(-2,0),(0,0),(0,-2)$ In a right angled triangle circumcentre is the mid-point of hypotenuse. $\therefore$ Point $(-1,-1)$ is the required coordinate of the circumcentre.
Hence, the correct answer is option: 'D'.