Q123 / 225 · JEE Main 2002 · Mathematics
The centre of the circle passing through $(0,0)$ and $(1,0)$ and touching the circle $x^2+y^2=9$ is
- A$\left(\frac{1}{2}, \frac{1}{2}\right)$
- Correct answerB$\left(\frac{1}{2},-\sqrt{2}\right)$
- C$\left(\frac{3}{2}, \frac{1}{2}\right)$
- D$\left(\frac{1}{2}, \frac{3}{2}\right)$
Hence, the correct answer is option: 'B'.