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Q123 / 225 · JEE Main 2002 · Mathematics

Q199 / 200 · JEE Main 2002 · Mathematics · Circle · Family of Circle

The centre of the circle passing through $(0,0)$ and $(1,0)$ and touching the circle $x^2+y^2=9$ is

  • A
    $\left(\frac{1}{2}, \frac{1}{2}\right)$
  • Correct answer
    B
    $\left(\frac{1}{2},-\sqrt{2}\right)$
  • C
    $\left(\frac{3}{2}, \frac{1}{2}\right)$
  • D
    $\left(\frac{1}{2}, \frac{3}{2}\right)$

Hence, the correct answer is option: 'B'.

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