Q122 / 160 · AP EAMCET 2020 (21 Sep Shift 1) · Physics

The central fringe in the interference pattern obtained in Young's double slit experiment will be a dark fringe when the phase difference between the waves from the two slits is

  • A
    zero
  • B
    \(\frac{\pi}{2}\)
  • Correct answer
    C
    \(\pi\)
  • D
    \(\frac{\pi}{3}\)

Solution

When the central fringe in the interference pattern in YDSE be a dark fringe, then path difference, will be \(\frac{\lambda}{2}\). i.e., \(\Delta x=\frac{\lambda}{2}\) \(\therefore\) Phase difference, \(\begin{aligned} \Delta \phi & =\frac{2 \pi}{\lambda} \times \Delta x \\ & =\frac{2 \pi}{\lambda} \times \frac{\lambda}{2}=\pi \end{aligned}\)

Hence, the correct answer is option: 'C'.

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