Q25 / 180 · COMEDK 2015 · Chemistry

The cathode reaction in the dry cell will be

  • A
    $\mathrm{Zn}(s) \longrightarrow \mathrm{Zn}^{2+}+2 e^{-}$
  • Correct answer
    B
    $\mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{--} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3}$
  • C
    $\mathrm{Zn}(\mathrm{Hg})+2 \mathrm{OH}^{-} \longrightarrow \mathrm{ZnO}(s)+\mathrm{H}_{2} \mathrm{O}+2 e^{-}$
  • D
    $\mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3} \longrightarrow \mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+2 e^{-}$

Solution

The cathode reaction in dry cell is $$ \mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{-} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3} $$

Hence, the correct answer is option: 'B'.

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