Q25 / 180 · COMEDK 2015 · Chemistry
The cathode reaction in the dry cell will be
- A$\mathrm{Zn}(s) \longrightarrow \mathrm{Zn}^{2+}+2 e^{-}$
- Correct answerB$\mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{--} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3}$
- C$\mathrm{Zn}(\mathrm{Hg})+2 \mathrm{OH}^{-} \longrightarrow \mathrm{ZnO}(s)+\mathrm{H}_{2} \mathrm{O}+2 e^{-}$
- D$\mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3} \longrightarrow \mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+2 e^{-}$
Solution
The cathode reaction in dry cell is
$$
\mathrm{MnO}_{2}+\mathrm{NH}_{4}^{+}+e^{-} \longrightarrow \mathrm{MnO}(\mathrm{OH})+\mathrm{NH}_{3}
$$
Hence, the correct answer is option: 'B'.