Q62 / 150 · MHT CET 2018 · Mathematics

The cartesian co-ordinates of the point on the parabola $y^{2} = - 16 x,$ whose parameter is $\frac{1}{2}$ are

A
$(- 2, 4)$
B
$(4, - 1)$
C
$(- 1, - 4)$
Correct answer
D
$(- 1, 4)$

Solution

Given

t = \frac{1}{2}; y^{2} = - 16 x

Comparing with standard parabola,

y^{2} = - 4 a x

We get

a = 4

P (t) = (- a t^{2}, 2 a t) = (- 4 \times \frac{1}{4}, 2 (\frac{1}{2} 4))

P (t) = (- 1, 4)

Hence, the correct answer is option: 'D'.

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