Q12 / 88 · NTA Abhyas (JEE Main) 2020 · Physics · Semiconductors

The carrier frequency generated by a circuit containing $1 nF$ capacitor and $10 μ H$ inductor is

A
$1592 Hz$
Correct answer
B
$1592 kHz$
C
$159.2 Hz$
D
$15.92 kHz$

Solution

C = 1 nF = 10^{- 9} F, L = 10 μH = 10^{- 5} H

f = \frac{1}{2 π \sqrt{LC}} = \frac{1}{2 π \sqrt{10^{- 5} \times 10^{- 9}}} = \frac{10^{7}}{2 π}

= 159 .2 \times 10^{4} Hz = 1592 kHz

Hence, the correct answer is option: 'B'.

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