Q123 / 150 · MHT CET 2024 (03 May Shift 2) · Physics
The Boolean expression for 'XOR' gate $C=(A \oplus B)$ is equal to
- A$(\mathrm{A} \cdot \mathrm{B})+(\overline{\mathrm{A}} \cdot \overline{\mathrm{B}})$
- B$\mathrm{A}+(\overline{\mathrm{A}} \cdot \overline{\mathrm{B}})$
- C$(\mathrm{A} \cdot \mathrm{B})+\overline{\mathrm{B}}$
- Correct answerD$(\overline{\mathrm{A}} \cdot \mathrm{B})+(\mathrm{A} \cdot \overline{\mathrm{B}})$
Solution
The Boolean expression of \(X O R\) gate is
\(y=A \oplus B=\bar{A} \cdot B+A \cdot \bar{B}\)
Hence, the correct answer is option: 'D'.