Q111 / 150 · MHT CET 2016 · Physics

The bob of a simple pendulum performs SHM with period T in air and with period T1 in water. Relation between T and T1 is (neglect friction due to water, density of the material of the bob is 98×103 k g /m3, density of water is1 g /cc)

  • Correct answer
    A
    T1=3T
  • B
    T1=2T
  • C
    T1=T
  • D
    T1=T2

Solution

T=2πlgeff
In air geff=g where as in water
geff=gσ-ρσ=9.898×103-10398×103
=9.898-198=9.8×18×89=9.89
∴  T1=2πlgeff=2π9lg
⇒ T 1 = 9 T=3T

Hence, the correct answer is option: 'A'.

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