Q160 / 180 · KCET 2015 · Physics
The average power dissipated in a pure inductor is
- A\( \frac{1}{2} \mathrm{VI} \)
- B\( \mathrm{VI}^{2} \)
- C\( \frac{\mathrm{VI}^{2}}{4} \)
- Correct answerDzero
Solution
Average power dissipated \( =P_{a v}=V I \cos \phi \)
In pure inductor, there is a phase difference of \( \pi / 2 \) between voltage and current. Therefore
\( \phi=\frac{\Pi}{2} \Rightarrow \cos \phi=0 \Rightarrow P_{a v}=0 \)
Thus, average power dissipated in a pure inductor is zero.
In pure inductor, there is a phase difference of \( \pi / 2 \) between voltage and current. Therefore
\( \phi=\frac{\Pi}{2} \Rightarrow \cos \phi=0 \Rightarrow P_{a v}=0 \)
Thus, average power dissipated in a pure inductor is zero.
Hence, the correct answer is option: 'D'.