Q94 / 155 · WBJEE 2023 · Mathematics

The average ordinate of \(y=\sin x\) over \([0, \pi]\) is

  • Correct answer
    A
    \(\frac{2}{\pi}\)
  • B
    \(\frac{3}{\pi}\)
  • C
    \(\frac{4}{\pi}\)
  • D
    \(\pi\)

Solution

Hint : As \(\sin x\) is a continuous function in \([0, \pi]\) Average ordinate will be \(=\frac{1}{\pi-0} \int_0^\pi \sin x d x=\frac{[-\cos x]_0^\pi}{\pi}=\frac{2}{\pi}\)

Hence, the correct answer is option: 'A'.

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