The atomic structure of He^(+) arises due to transition from n_2 to n_1 level. If n_1+n_2 is 3 and n_2-n_1 is 1. Find the λ in nm of transition for…

Question

The atomic structure of He^(+) arises due to transition from n_2 to n_1 level. If n_1+n_2 is 3 and n_2-n_1 is 1. Find the λ in nm of transition for this series in He^(+) in nm.

MARKS Content Team · Accepted Answer

Correct answer: 30. n_1+n_2=3 …(i) n_2-n_1=1 …(ii) 2n_2=4 So n_2=2 Putting the value of n_2 in (i) n_1=3-n_2=3-2=1 1/(λ)=Rz^21/n12-1/n22=R.2^21/(1^2)-1/(2^2) λ=1/3R=1/(3×109678cm^(-1)) =3×10^(-6)cm=3×10^(-6)×10^7=30 nm.

The atomic structure of $H e^{+}$ arises due to transition from $n_{2}$ to $n_{1}$ level. If $n_{1} + n_{2}$ is 3 and $n_{2} - n_{1}$ is 1. Find the $λ$ in nm of transition for this series in $H e^{+}$ in nm.

Solution

More Structure of Atom Questions

The atomic structure of He+ arises due to transition from n2 to n1 level. If n1+n2 is 3 and n2-n1 is 1. Find the λ in nm of transition for this series in He+ in nm.

Solution

More Structure of Atom Questions

The atomic structure of $H e^{+}$ arises due to transition from $n_{2}$ to $n_{1}$ level. If $n_{1} + n_{2}$ is 3 and $n_{2} - n_{1}$ is 1. Find the $λ$ in nm of transition for this series in $H e^{+}$ in nm.