The atomic number (Z) of an element whose k_a wavelength is λ is 11. The atomic number of an element whose k_a , wavelength is 4 λ is equal to

Correct answer: (A) 6. (Z-1)^2 λ = constant ∴ (10^2 ) λ =4 λ(Z-1)^2 ⇒ Z =6

Q200 / 200 · Manipal (MET) 2014 · Physics

The atomic number (Z) of an element whose $k_a$ wavelength is $\lambda$ is 11. The atomic number of an element whose $k_a$, wavelength is $4 \lambda$ is equal to

Correct answer
A
6
B
11
C
44
D
4

Solution

$\begin{aligned} & & (Z-1)^2 \lambda & =\text { constant } \\ & \therefore & \left(10^2\right) \lambda & =4 \lambda(Z-1)^2 \\ \Rightarrow & & Z & =6\end{aligned}$

Hence, the correct answer is option: 'A'.

The atomic number (Z) of an element whose $k_a$ wavelength is $\lambda$ is 11. The atomic number of an element whose $k_a$, wavelength is $4 \lambda$ is equal to

Solution

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