The area of the region bounded by the $y$-axis, $y=\cos x, y=\sin x$, when $0 \leq x \leq \frac{\pi}{4}$, is

• Correct answer
  A

  $(\sqrt{2}-1)$ sq. units
• B

  $2(\sqrt{2}-1)$ sq. units
• C

  $(\sqrt{2}+1)$ sq. units
• D

  $\sqrt{2}$ sq. units

Solution

$\begin{aligned} & =\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)-(0+1) \\ & =\sqrt{2}-1\end{aligned}$

Hence, the correct answer is option: 'A'.