Q110 / 160 · WBJEE 2012 · Mathematics
The area of the region bounded by the curves $y=x^{3}, y=\frac{1}{x}, x=2$ is
- A$4-\log _{e} 2$
- Correct answerB$\frac{1}{4}+\log _{e} 2$
- C$3-\log _{e} 2$
- D$\frac{15}{4}-\log _{e} 2$
Solution
First of all we draw the graph $y=x^{3}, y=\frac{1}{x}, x=2$
Required area i.e., (OMPNO) $=\int_{0}^{1} x^{3} d x+\int_{1}^{2} \frac{1}{x} d x$
$=\left[\frac{x^{4}}{4}\right]_{0}+\left[\log _{4} x\right]_{1}^{2}=\frac{1}{4}+\log _{c} 2$
Required area i.e., (OMPNO) $=\int_{0}^{1} x^{3} d x+\int_{1}^{2} \frac{1}{x} d x$
$=\left[\frac{x^{4}}{4}\right]_{0}+\left[\log _{4} x\right]_{1}^{2}=\frac{1}{4}+\log _{c} 2$Hence, the correct answer is option: 'B'.