The area of a rectangular field (in ${\mathrm{m}}^2$) of length $55.3 \mathrm{m}$ and breadth $25 \mathrm{m}$ after rounding off the value for correct significant digits is:

Length has 3 significant digits and breadth has 2 significant digits, hence the product should have least number of significant digits which is 2.

Area of rectangular field is, $A=\mathrm{length}\times \mathrm{breadth}$

$=55.3 \mathrm{m}\times 25 \mathrm{m}=1382.5 {\mathrm{m}}^2$

Thus, area of rectangular field upto correct significant figure is $14\times {10}^2$.